์ „์ฒด ๊ธ€

์ „์ฒด ๊ธ€

    [๋ฐฑ์ค€] 11054๋ฒˆ - ๊ฐ€์žฅ ๊ธด ๋ฐ”์ดํ† ๋‹‰ ๋ถ€๋ถ„ ์ˆ˜์—ด

    [๋ฐฑ์ค€] 11054๋ฒˆ - ๊ฐ€์žฅ ๊ธด ๋ฐ”์ดํ† ๋‹‰ ๋ถ€๋ถ„ ์ˆ˜์—ด

    ๋ฌธ์ œ ๋ฌธ์ œ์ˆ˜์—ด S๊ฐ€ ์–ด๋–ค ์ˆ˜ Sk๋ฅผ ๊ธฐ์ค€์œผ๋กœ S1 Sk+1 > ... SN-1 > SN์„ ๋งŒ์กฑํ•œ๋‹ค๋ฉด, ๊ทธ ์ˆ˜์—ด์„ ๋ฐ”์ดํ† ๋‹‰ ์ˆ˜์—ด์ด๋ผ๊ณ  ํ•œ๋‹ค.์˜ˆ๋ฅผ ๋“ค์–ด, {10, 20, 30, 25, 20}๊ณผ {10, 20, 30, 40}, {50, 40, 25, 10} ์€ ๋ฐ”์ดํ† ๋‹‰ ์ˆ˜์—ด์ด์ง€๋งŒ, {1, 2, 3, 2, 1, 2, 3, 2, 1}๊ณผ {10, 20, 30, 40, 20, 30} ์€ ๋ฐ”์ดํ† ๋‹‰ ์ˆ˜์—ด์ด ์•„๋‹ˆ๋‹ค.์ˆ˜์—ด A๊ฐ€ ์ฃผ์–ด์กŒ์„ ๋•Œ, ๊ทธ ์ˆ˜์—ด์˜ ๋ถ€๋ถ„ ์ˆ˜์—ด ์ค‘ ๋ฐ”์ดํ† ๋‹‰ ์ˆ˜์—ด์ด๋ฉด์„œ ๊ฐ€์žฅ ๊ธด ์ˆ˜์—ด์˜ ๊ธธ์ด๋ฅผ ๊ตฌํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค. ์ž…๋ ฅ์ฒซ์งธ ์ค„์— ์ˆ˜์—ด A์˜ ํฌ๊ธฐ N์ด ์ฃผ์–ด์ง€๊ณ , ๋‘˜์งธ ์ค„์—๋Š” ์ˆ˜์—ด A๋ฅผ ์ด๋ฃจ๊ณ  ์žˆ๋Š” Ai๊ฐ€ ์ฃผ์–ด์ง„๋‹ค. (1 ≤ N ≤ 1,000, 1 ≤ Ai ≤ 1..

    [๋ฐฑ์ค€] 11722๋ฒˆ - ๊ฐ€์žฅ ๊ธด ๊ฐ์†Œํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด

    ๋ฌธ์ œ ๋ฌธ์ œ ์ˆ˜์—ด A๊ฐ€ ์ฃผ์–ด์กŒ์„ ๋•Œ, ๊ฐ€์žฅ ๊ธด ๊ฐ์†Œํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด์„ ๊ตฌํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค. ์˜ˆ๋ฅผ ๋“ค์–ด, ์ˆ˜์—ด A = {10, 30, 10, 20, 20, 10} ์ธ ๊ฒฝ์šฐ์— ๊ฐ€์žฅ ๊ธด ๊ฐ์†Œํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด์€A = {10, 30, 10, 20, 20, 10} ์ด๊ณ , ๊ธธ์ด๋Š” 3์ด๋‹ค. ์ž…๋ ฅ ์ฒซ์งธ ์ค„์— ์ˆ˜์—ด A์˜ ํฌ๊ธฐ N (1 ≤ N ≤ 1,000)์ด ์ฃผ์–ด์ง„๋‹ค. ๋‘˜์งธ ์ค„์—๋Š” ์ˆ˜์—ด A๋ฅผ ์ด๋ฃจ๊ณ  ์žˆ๋Š” Ai๊ฐ€ ์ฃผ์–ด์ง„๋‹ค. (1 ≤ Ai ≤ 1,000) ์ถœ๋ ฅ ์ฒซ์งธ ์ค„์— ์ˆ˜์—ด A์˜ ๊ฐ€์žฅ ๊ธด ๊ฐ์†Œํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด์˜ ๊ธธ์ด๋ฅผ ์ถœ๋ ฅํ•œ๋‹ค. ํ’€์ด๊ณผ์ • 1.๊ทœ์น™DP์ด๋ฏ€๋กœ ์ ํ™”์‹๊ณผ ๋ฉ”๋ชจ์ด์ œ์ด์…˜์„ ์ด์šฉํ•ฉ๋‹ˆ๋‹ค.d[n-1] > d[n] ์ด๋ผ๋ฉด d[n]์˜ ๊ฐ’์„ ์ฆ๊ฐ€์‹œํ‚ต๋‹ˆ๋‹ค. 2.์ˆœ์„œ [11053๋ฒˆ - ๊ฐ€์žฅ ๊ธด ์ฆ๊ฐ€ํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด] ๋ฌธ์ œ์™€ ๊ฐ™์€ ์›..

    [๋ฐฑ์ค€] 11055๋ฒˆ - ๊ฐ€์žฅ ํฐ ์ฆ๊ฐ€ ๋ถ€๋ถ„ ์ˆ˜์—ด(์ˆ˜์ •)

    [๋ฐฑ์ค€] 11055๋ฒˆ - ๊ฐ€์žฅ ํฐ ์ฆ๊ฐ€ ๋ถ€๋ถ„ ์ˆ˜์—ด(์ˆ˜์ •)

    ๋ฌธ์ œ ๋ฌธ์ œ์ˆ˜์—ด A๊ฐ€ ์ฃผ์–ด์กŒ์„ ๋•Œ, ๊ทธ ์ˆ˜์—ด์˜ ์ฆ๊ฐ€ ๋ถ€๋ถ„ ์ˆ˜์—ด ์ค‘์—์„œ ํ•ฉ์ด ๊ฐ€์žฅ ํฐ ๊ฒƒ์„ ๊ตฌํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค.์˜ˆ๋ฅผ ๋“ค์–ด, ์ˆ˜์—ด A = {1, 100, 2, 50, 60, 3, 5, 6, 7, 8} ์ธ ๊ฒฝ์šฐ์— ํ•ฉ์ด ๊ฐ€์žฅ ํฐ ์ฆ๊ฐ€ ๋ถ€๋ถ„ ์ˆ˜์—ด์€ A = {1, 100, 2, 50, 60, 3, 5, 6, 7, 8} ์ด๊ณ , ํ•ฉ์€ 113์ด๋‹ค. ์ž…๋ ฅ์ฒซ์งธ ์ค„์— ์ˆ˜์—ด A์˜ ํฌ๊ธฐ N (1 ≤ N ≤ 1,000)์ด ์ฃผ์–ด์ง„๋‹ค.๋‘˜์งธ ์ค„์—๋Š” ์ˆ˜์—ด A๋ฅผ ์ด๋ฃจ๊ณ  ์žˆ๋Š” Ai๊ฐ€ ์ฃผ์–ด์ง„๋‹ค. (1 ≤ Ai ≤ 1,000) ์ถœ๋ ฅ์ฒซ์งธ ์ค„์— ์ˆ˜์—ด A์˜ ํ•ฉ์ด ๊ฐ€์žฅ ํฐ ์ฆ๊ฐ€ ๋ถ€๋ถ„ ์ˆ˜์—ด์˜ ํ•ฉ์„ ์ถœ๋ ฅํ•œ๋‹ค. ํ’€์ด๊ณผ์ • 1.๊ทœ์น™DP์ด๋ฏ€๋กœ ์ ํ™”์‹๊ณผ ๋ฉ”๋ชจ์ด์ œ์ด์…˜์„ ์ด์šฉํ•ฉ๋‹ˆ๋‹ค.d[n-1] < d[n] ์ด๋ผ๋ฉด d[n]์˜ ๊ฐ’์„ ์ฆ๊ฐ€์‹œํ‚ต๋‹ˆ๋‹ค. 2.์ˆœ์„œ[1105..

    [๋ฐฑ์ค€] 11053๋ฒˆ - ๊ฐ€์žฅ ๊ธด ์ฆ๊ฐ€ํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด

    [๋ฐฑ์ค€] 11053๋ฒˆ - ๊ฐ€์žฅ ๊ธด ์ฆ๊ฐ€ํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด

    ๋ฌธ์ œ ๋ฌธ์ œ์ˆ˜์—ด A๊ฐ€ ์ฃผ์–ด์กŒ์„ ๋•Œ, ๊ฐ€์žฅ ๊ธด ์ฆ๊ฐ€ํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด์„ ๊ตฌํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค.์˜ˆ๋ฅผ ๋“ค์–ด, ์ˆ˜์—ด A = {10, 20, 10, 30, 20, 50} ์ธ ๊ฒฝ์šฐ์— ๊ฐ€์žฅ ๊ธด ์ฆ๊ฐ€ํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด์€ A = {10, 20, 10, 30, 20, 50} ์ด๊ณ , ๊ธธ์ด๋Š” 4์ด๋‹ค. ์ž…๋ ฅ์ฒซ์งธ ์ค„์— ์ˆ˜์—ด A์˜ ํฌ๊ธฐ N (1 ≤ N ≤ 1,000)์ด ์ฃผ์–ด์ง„๋‹ค.๋‘˜์งธ ์ค„์—๋Š” ์ˆ˜์—ด A๋ฅผ ์ด๋ฃจ๊ณ  ์žˆ๋Š” Ai๊ฐ€ ์ฃผ์–ด์ง„๋‹ค. (1 ≤ Ai ≤ 1,000) ์ถœ๋ ฅ์ฒซ์งธ ์ค„์— ์ˆ˜์—ด A์˜ ๊ฐ€์žฅ ๊ธด ์ฆ๊ฐ€ํ•˜๋Š” ๋ถ€๋ถ„ ์ˆ˜์—ด์˜ ๊ธธ์ด๋ฅผ ์ถœ๋ ฅํ•œ๋‹ค. ํ’€์ด๊ณผ์ • 1.๊ทœ์น™DP์ด๋ฏ€๋กœ ์ ํ™”์‹๊ณผ ๋ฉ”๋ชจ์ด์ œ์ด์…˜์„ ์ด์šฉํ•ฉ๋‹ˆ๋‹ค.d[n-1] < d[n] ์ด๋ผ๋ฉด d[n]์˜ ๊ฐ’์„ ์ฆ๊ฐ€์‹œํ‚ต๋‹ˆ๋‹ค. 2.์ˆœ์„œ ๋ฉ”๋ชจ์ด์ œ์ด์…˜์— ํšŸ์ˆ˜๋ฅผ ์ €์žฅํ•˜๋Š” ์ ํ™”์‹์„ ์ƒ๊ฐํ•ด ๋ด…๋‹ˆ๋‹ค.์ฒซ์งธ๋กœ, A[n-..

    [๋งค์ผํ”„๋กœ๊ทธ๋ž˜๋ฐ] ์ฝ”๋”ฉํ…Œ์ŠคํŠธ 07/08/2019

    ๋ฌธ์ œ ์ •์ˆ˜ ๋ฐฐ์—ด(int array)๊ฐ€ ์ฃผ์–ด์ง€๋ฉด ๊ฐ€์žฅ ํฐ ์ด์–ด์ง€๋Š” ์›์†Œ๋“ค์˜ ํ•ฉ์„ ๊ตฌํ•˜์‹œ์˜ค. ๋‹จ, ์‹œ๊ฐ„๋ณต์žก๋„๋Š” O(n).Given an integer array, find the largest consecutive sum of elements. ์˜ˆ์ œ}Input: [-1, 3, -1, 5]Output: 7 // 3 + (-1) + 5 Input: [-5, -3, -1]Output: -1 // -1 Input: [2, 4, -2, -3, 8]Output: 9 // 2 + 4 + (-2) + (-3) + 8 ๋‚ด๊ฐ€ ์ƒ๊ฐํ•ด๋ณธ ํ’€์ด๊ณผ์ • 1.๊ทœ์น™์‹œ๊ฐ„ ๋ณต์žก๋„๋Š” O(n)์ž…๋‹ˆ๋‹ค.๋”ํ•ด์ง€๋Š” ์›์†Œ๋Š” ๋ฐ˜๋“œ์‹œ ์ธ๋ฑ์Šค๊ฐ€ ์ด์–ด์ ธ ์žˆ์–ด์•ผ ํ•ฉ๋‹ˆ๋‹ค. (arr[i] + arr[i+3] ๊ฐ™์€ ๊ฒฝ์šฐ๋Š” X) 2.์ˆœ์„œ ์‹œ๊ฐ„๋ณต์žก๋„๊ฐ€ O(n)์ด๋‹ˆ 2์ค‘ f..

    [๋ฐฑ์ค€] 2156๋ฒˆ - ํฌ๋„์ฃผ ์‹œ์‹

    [๋ฐฑ์ค€] 2156๋ฒˆ - ํฌ๋„์ฃผ ์‹œ์‹

    ๋ฌธ์ œ ๋ฌธ์ œํšจ์ฃผ๋Š” ํฌ๋„์ฃผ ์‹œ์‹ํšŒ์— ๊ฐ”๋‹ค. ๊ทธ ๊ณณ์— ๊ฐ”๋”๋‹ˆ, ํ…Œ์ด๋ธ” ์œ„์— ๋‹ค์–‘ํ•œ ํฌ๋„์ฃผ๊ฐ€ ๋“ค์–ด์žˆ๋Š” ํฌ๋„์ฃผ ์ž”์ด ์ผ๋ ฌ๋กœ ๋†“์—ฌ ์žˆ์—ˆ๋‹ค. ํšจ์ฃผ๋Š” ํฌ๋„์ฃผ ์‹œ์‹์„ ํ•˜๋ ค๊ณ  ํ•˜๋Š”๋ฐ, ์—ฌ๊ธฐ์—๋Š” ๋‹ค์Œ๊ณผ ๊ฐ™์€ ๋‘ ๊ฐ€์ง€ ๊ทœ์น™์ด ์žˆ๋‹ค.ํฌ๋„์ฃผ ์ž”์„ ์„ ํƒํ•˜๋ฉด ๊ทธ ์ž”์— ๋“ค์–ด์žˆ๋Š” ํฌ๋„์ฃผ๋Š” ๋ชจ๋‘ ๋งˆ์…”์•ผ ํ•˜๊ณ , ๋งˆ์‹  ํ›„์—๋Š” ์›๋ž˜ ์œ„์น˜์— ๋‹ค์‹œ ๋†“์•„์•ผ ํ•œ๋‹ค.์—ฐ์†์œผ๋กœ ๋†“์—ฌ ์žˆ๋Š” 3์ž”์„ ๋ชจ๋‘ ๋งˆ์‹ค ์ˆ˜๋Š” ์—†๋‹ค.ํšจ์ฃผ๋Š” ๋  ์ˆ˜ ์žˆ๋Š” ๋Œ€๋กœ ๋งŽ์€ ์–‘์˜ ํฌ๋„์ฃผ๋ฅผ ๋ง›๋ณด๊ธฐ ์œ„ํ•ด์„œ ์–ด๋–ค ํฌ๋„์ฃผ ์ž”์„ ์„ ํƒํ•ด์•ผ ํ• ์ง€ ๊ณ ๋ฏผํ•˜๊ณ  ์žˆ๋‹ค. 1๋ถ€ํ„ฐ n๊นŒ์ง€์˜ ๋ฒˆํ˜ธ๊ฐ€ ๋ถ™์–ด ์žˆ๋Š” n๊ฐœ์˜ ํฌ๋„์ฃผ ์ž”์ด ์ˆœ์„œ๋Œ€๋กœ ํ…Œ์ด๋ธ” ์œ„์— ๋†“์—ฌ ์žˆ๊ณ , ๊ฐ ํฌ๋„์ฃผ ์ž”์— ๋“ค์–ด์žˆ๋Š” ํฌ๋„์ฃผ์˜ ์–‘์ด ์ฃผ์–ด์กŒ์„ ๋•Œ, ํšจ์ฃผ๋ฅผ ๋„์™€ ๊ฐ€์žฅ ๋งŽ์€ ์–‘์˜ ํฌ๋„์ฃผ๋ฅผ ๋งˆ์‹ค ์ˆ˜ ์žˆ๋„๋ก ํ•˜๋Š” ํ”„๋กœ๊ทธ๋žจ์„ ์ž‘์„ฑํ•˜์‹œ์˜ค. ์˜ˆ๋ฅผ ๋“ค์–ด 6..

    [๊ฟ€ํŒ] ํฌ๋กฌ ์‚ฌ์šฉ์‹œ ์œ ํŠœ๋ธŒ ํ”„๋ฆฌ์ง• ํ˜„์ƒ ํ•ด๊ฒฐ ๋ฐฉ๋ฒ•

    ํฌ๋กฌ 'ํ•˜๋“œ์›จ์–ด ๊ฐ€์† ์‚ฌ์šฉ'์œผ๋กœ ํ”„๋ฆฌ์ง• ํ˜„์ƒ์ด ์ƒ๊ธฐ๋Š” ๊ฒฝ์šฐhttp://blog.naver.com/PostView.nhn?blogId=chloeagit&logNo=221240267372&parentCategoryNo=&categoryNo=34&viewDate=&isShowPopularPosts=true&from=search ๋ผ๋ฐ์˜จ ๊ทธ๋ž˜ํ”ฝ์นด๋“œ ์‚ฌ์šฉ์‹œ ํ”„๋ฆฌ์ง• ํ˜„์ƒ์ด ์ƒ๊ธฐ๋Š” ๊ฒฝ์šฐhttps://quasarzone.co.kr/bbs/board.php?bo_table=qf_hwjoin&wr_id=140547

    [LeetCode] 1108๋ฒˆ - Defanging an IP Address(IP์ฃผ์†Œ ๋ชป์“ฐ๊ฒŒ ๋งŒ๋“ค๊ธฐ)

    ๋ฌธ์ œ 1108. Defanging an IP AddressEasy1687FavoriteShareGiven a valid (IPv4) IP address, return a defanged version of that IP address.A defanged IP address replaces every period "." with "[.]". Example 1:Input: address = "1.1.1.1" Output: "1[.]1[.]1[.]1" Example 2:Input: address = "255.100.50.0" Output: "255[.]100[.]50[.]0" Constraints:The given address is a valid IPv4 address. ํ’€์ด๊ณผ์ • 1.๊ทœ์น™IPv4 ์ฃผ์†Œ์ธ ์›๋ฐฐ..

    [LeetCode] 4๋ฒˆ - Median of Two Sorted Arrays(๋‘ ์ •๋ ฌ๋œ ๋ฐฐ์—ด์˜ ์ค‘์•™๊ฐ’)

    [LeetCode] 4๋ฒˆ - Median of Two Sorted Arrays(๋‘ ์ •๋ ฌ๋œ ๋ฐฐ์—ด์˜ ์ค‘์•™๊ฐ’)

    ๋ฌธ์ œ 4. Median of Two Sorted ArraysHard4544636FavoriteShareThere are two sorted arrays nums1 and nums2 of size m and n respectively.Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).You may assume nums1 and nums2 cannot be both empty.Example 1:nums1 = [1, 3] nums2 = [2] The median is 2.0 Example 2:nums1 = [1, 2] nums2 = [3, 4] The median is (2 + 3)/2 ..

    [๋ฐฑ์ค€] 9456๋ฒˆ - ์Šคํ‹ฐ์ปค

    [๋ฐฑ์ค€] 9456๋ฒˆ - ์Šคํ‹ฐ์ปค

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    [๊ฐœ์ธ ๋ ˆํผ๋Ÿฐ์Šค] mathJax ๋ฌธ๋ฒ• ์‚ฌ์šฉํ• ๋•Œ๋งˆ๋‹ค ์ •๋ฆฌํ•ด๋‘๋Š” ๊ธ€

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    [์œˆ๋„์šฐ(Windows)] powershell, Git bash, command prompt๊ฐ„์˜ ์ฐจ์ด์ 

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